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Germany / Leipzig 2018 / Doubles Open · Men / Season 1 (2018/19)

Andrej Lichtenberg & Roman Schadt — Leipzig 2018

Roman Schadt Andrej Lichtenberg
M 30-39 n = 20
Finish · net time
1:01:06
−20:34 v median 1:21:40
Men
1/20
30-39
1/14
Field beaten
95%

The race, in three figures

Biggest gain
100m Sandbag Lunges
−1:32
v median
2/20
Rank
Biggest loss
1000m Row
+21:07
v median
20/20
Rank

The race, in words

1:01:06 won the Doubles Open division at Leipzig 2018 for Andrej Lichtenberg & Roman Schadt, first of 20 men's teams.

Nowhere gained more than the sandbag lunges: 1:32 on the median. The row cost the most time: 21:07 slower than the median.

Eight blocks

Bar = field beaten · tick = median

  1. Block 01 7:45
    Running 1 4:06
    v median −0:49
    1000m SkiErg 3:39
    v median −0:32
  2. Block 02 5:29
    Running 2 4:24
    v median −1:02
    50m Sled Push 1:05
    v median −0:27
  3. Block 03 7:12
    Running 3 4:36
    v median −1:13
    50m Sled Pull 2:36
    v median −0:31
  4. Block 04 6:32
    Running 4 4:29
    v median −1:18
    80m Burpee Broad Jump 2:03
    v median −1:24
  5. Block 05 30:22
    Running 5 4:36
    v median −1:19
    1000m Row 25:46
    v median +21:07
  6. Block 06 5:48
    Running 6 4:25
    v median −1:14
    200m Farmers Carry 1:23
    v median −0:15
  7. Block 07 6:36
    Running 7 4:31
    v median −0:59
    100m Sandbag Lunges 2:05
    v median −1:32
  8. Block 08 8:07
    Running 8 4:42
    v median −1:26
    Wall Balls 3:25
    v median −1:03

Against the middle of your field

Men · n = 20

A pace, not a person: at every mat, the middle of the 20 men's teams who finished.

20:00 10:00 10:00 Finish Finish Finish Finish Finish Finish Finish Finish Finish Middle ↑ You ahead ↓ Field ahead 20:34
You ahead Field ahead Middle half · 25th–75th Crossed the middle · 0 Finish · 20:34 ahead

Elsewhere

The board

Doubles Open · Men at Leipzig 2018

See this race on page 1
Source Official
Event
Leipzig 2018
Division
HYROX DOUBLES
Contest
HD_999999212F07B50000000015
Measured against
Men · n = 20